Design
Procedure with Relevant Equations for Tall Distillation Column with varying
Thickness
fds = Weight of shell / Cross section of shell
Here,
fdins = π Dins tins ρins X
Here, Dins = Diameter of Insulation
Here,
Here,
fdx = fds + fdins + fd(liq) + fd(att)
4) Stress due to wind load at a distance X :-
fwx = Mw / Z
Here, Z = Modules of Section for the area of shell
5) Determination of Height (X) :-
fwx + fap - fdx = ft(max)
Here, ft(max) = Permissible Tensile Stress of shell material
fe = We X e / π/4 DO 2 ( ts - c)
Here, We = Summation of Eccentric load
fsx = Msx / π/4 DO 2 ( ts - c)
Where,
1) Column Shell Thickness ( ts
)
:- The maximum thickness is at the top of the shell end and is
determined only on the basis of
Circumferential Stresses.
ts = (PDi / 2fJ – P) + c
Here , ts = Shell Thickness (unit -
mm)
P = Design Pressure
Di = Inner diameter of shell
f = Allowable stress of shell material
J = Joint Efficiency = 1(for distillation column)
c = Corrosion Allowance
Note :- All stresses are in N/mm2
2) Axial Stress Due to
Pressure
(fap) :-
fap =
PDi / 4 ( ts - c)
Here , P = Design Pressure
Di = Inner diameter of shell
ts = Shell Thickness that calculated
above
c = Corrosion Allowance
Axial Stress Due to Pressure is the same throughout the column
height.
3) Stresses due to Dead
Loads
:-
A) Compressive stress due
to weight of shell at height ‘X’ :-
fds = Weight of shell / Cross section of shell
= π/4 (DO
2 -
Di 2)
ρshell X
π/4 (DO 2 -
Di 2)
Here,
Outer diameter of shell (DO)= Di + 2 ts
ρshell = Density of shell material
X = Height of column under consideration
B) Compressive stress due
to weight of Insulation at height ‘X’ :-
fdins = π Dins tins ρins X
π Dm ( ts
- c)
= Weight of insulation
per unit height X
π Dm ( ts
- c)
Here, Dins = Diameter of Insulation
tins = Thickness of insulation
ρins = Density of insulation
Dm = Mean diameter of shell= (DO + Di )/2
C) Compressive stress due
to weight of liquid in the column up to a height ‘X’ :-
fd(liq) = ∑ Weight of liquid
per unit height X
π
Dm ( ts - c)
Here,
Weight in terms
of height X is given by
= (X / tray
spacing ) π/4 Di 2 x Weight of liquid,tray etc.
D) Compressive stress due
to weight of attachments such as internals, tophead, platforms and ladder up to
a height ‘X’ :-
fd(att) = ∑ Weight of
attachments per unit height X
π
Dm ( ts - c)
Here,
fd(att) = Weight of head +
(Weight of attachments x (X))
π Dm ( ts
- c)
E) Total Compressive Dead
Weight stress (fdx ) :-
fdx = fds + fdins + fd(liq) + fd(att)
4) Stress due to wind load at a distance X :-
fwx = Mw / Z
Here, Z = Modules of Section for the area of shell
= π/4 DO 2 ( ts - c)
Mw = Bending moment due to
wind load at a distance X
= Wind
load x Distance / 2
= 0.7 Pw DO X2 / 2
Here, Pw = Wind Pressure
fwx = 1.4 Pw X2 / π Do ( ts - c)
5) Determination of Height (X) :-
fwx + fap - fdx = ft(max)
Here, ft(max) = Permissible Tensile Stress of shell material
If Joint Efficiency J is to be considered,then,
fwx + fap - fdx - fall x J = 0
The above equation can be stated in the form of
quadratic equation, a X2 + b
X + c = 0 , from which we can find the value of X.
6) Stress due to
Eccentricity load (fe) :-
fe = We X e / π/4 DO 2 ( ts - c)
Here, We = Summation of Eccentric load
e = Eccentricity
7) Stress due to Seismic
load (fsx) :-
fsx = Msx / π/4 DO 2 ( ts - c)
Where,
Msx = Bending Moment at X
= 4SWX2 (3H - X / H2)
S
– Semismic coefficient
W
– Total weight of column
H
– Total height of column
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